2026-04-20

Problem — 2026-04-20

Easy

Easycombinatorics

A 3×33 \times 3 grid is to be filled with the digits 11 through 99 (each used exactly once). How many ways can the first row be filled so that its entries are in increasing order from left to right?

Enter an integer

Show solution
We need to choose which 33 of the 99 digits go in the first row; the increasing-order requirement means there is exactly one arrangement for each choice. So the answer is (93)=9!3!6!=84\binom{9}{3} = \frac{9!}{3! \cdot 6!} = 84.