2026-04-14

Problem — 2026-04-14

Easy

Easycombinatorics

How many distinct ways can the set {1,2,3,4}\{1, 2, 3, 4\} be partitioned into exactly 22 non-empty subsets?

Enter an integer

Show solution
The partitions are determined by which subset contains 11. The other subset can be any non-empty proper subset of {2,3,4}\{2,3,4\}: namely {2,3,4}\{2,3,4\}, {2,3}\{2,3\}, {2,4}\{2,4\}, {3,4}\{3,4\}, {2}\{2\}, {3}\{3\}, or {4}\{4\} — giving 77 partitions. (Equivalently, 231=72^3 - 1 = 7, since we exclude the case where the other subset is empty.)