2026-04-03

Problem — 2026-04-03

Medium

Mediumalgebra

What is the value of n=1n2n\displaystyle\sum_{n=1}^{\infty} \frac{n}{2^n}?

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Let S=12+24+38+416+S = \frac{1}{2} + \frac{2}{4} + \frac{3}{8} + \frac{4}{16} + \cdots. Then S2=14+28+316+\frac{S}{2} = \frac{1}{4} + \frac{2}{8} + \frac{3}{16} + \cdots. Subtracting: SS2=12+14+18+=1S - \frac{S}{2} = \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots = 1. So S2=1\frac{S}{2} = 1, giving S=2S = 2.