2026-04-02

Problem — 2026-04-02

Hard

Hardprobability

What is the expected number of rolls of a fair six-sided die needed to see all 66 faces at least once?

Express as a fraction or decimal

Show solution
After seeing kk distinct faces, the probability of a new face on the next roll is 6k6\frac{6-k}{6}, so the expected rolls until a new face is 66k\frac{6}{6-k}. Total: 66+65+64+63+62+61=1+1.2+1.5+2+3+6=14.7=14710\frac{6}{6} + \frac{6}{5} + \frac{6}{4} + \frac{6}{3} + \frac{6}{2} + \frac{6}{1} = 1 + 1.2 + 1.5 + 2 + 3 + 6 = 14.7 = \frac{147}{10}.